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Ilias95 έγραψε:
13.
Εκφώνηση:

Spoiler: show

Write a program that calculates the average world length for a sentence.
For simplicity, your program should consider a punctuation mark to be part of the word to wich it is attached.
Display the average word length to one decimal place.

Λύση:

Spoiler: show

Μορφοποιημένος Κώδικας: Επιλογή όλων

#include <stdio.h>

int main(void)
{
    char ch;
    int words = 1, digits = 0;
    
    printf("Enter a sentence: ");    
    
    while ((ch = getchar()) != '\n') {
        if (ch == ' ')
            words++; 
        else
            digits++;
    }
    
    printf("Avarage word length: %.1f", (float) digits / words);
    
    return 0;
}

Μορφοποιημένος Κώδικας: Επιλογή όλων

#include <stdio.h>
#include <ctype.h>		/* for isalnum() */

int main( void )
{
	int ch = '\0';
	int wcount = 0, letcount = 0;

	printf("Enter a sentence: ");    

	for (;;)					/* infinite loop              */
	{
		ch = getchar();
		if ( isalnum(ch) )
			letcount++; 
		else {
			if ( letcount )			/* ignore leading blanks      */
				wcount++;
			/* ignore invalid (non-word) letters */
			while ( '\n' != ch && !isalnum(ch=getchar()) )
				;
			if ( '\n' == ch )
				break;			/* exit infinite loop          */
			letcount++;			/* count any last valid letter */
		}
	}

	printf( "%d word(s), %d letter(s)\n", wcount, letcount );
	printf( "Avarage word length: %.1f\n", !wcount ? 0 : (float)letcount/wcount );

	return 0;
}